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3x^2-57x+264=0
a = 3; b = -57; c = +264;
Δ = b2-4ac
Δ = -572-4·3·264
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-57)-9}{2*3}=\frac{48}{6} =8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-57)+9}{2*3}=\frac{66}{6} =11 $
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